You Toss A Coin And Roll A Dice. What Is P(tails and a 6)?

Answer is 1/12

Since the events are independent,
$P\left(tails\text{and}6\right)=P\left(tails\right)\cdot P\left(6\right)$
$P\left(tails\text{and}6\right)=\frac{\mathrm{1/}}{2}\cdot \frac{1}{\mathrm{/6}}$
P(tails and 6)=1/12